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Tree-Like Continua Do Not Admit Expansive Homeomorphisms, Papers of Mathematics

A research article published in the american mathematical society, which discusses the properties of expansive homeomorphisms and their relationship to tree-like continua. The article shows that tree-like continua do not admit expansive homeomorphisms, and provides proof for this result. Expansive homeomorphisms are a type of continuous function that stretches subcontinua, and are known to exhibit chaotic behavior. The document also mentions examples of continua that do admit expansive homeomorphisms, such as plykin's attractors and the dyadic solenoid.

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PROCEEDINGS OF THE
AMERICAN MATHEMATICAL SOCIETY
Volume 130, Number 11, Pages 3409–3413
S 0002-9939(02)06447-X
Article electronically published on May 14, 2002
TREE-LIKE CONTINUA DO NOT ADMIT
EXPANSIVE HOMEOMORPHISMS
CHRISTOPHER MOURON
(Communicated by Alan Dow)
Abstract. A homeomorphism h:XXis called expansive provided that
for some fixed c>0andeveryx, y Xthere exists an integer n, dep endent
only on xand y, such that d(hn(x),h
n(y)) >c.ItisshownthatifXis a
tree-like continuum, then hcannot be expansive.
1. Introduction
Acontinuum is a nondegenerate compact connected metric space. A homeo-
morphism h:XXis called expansive provided that for some fixed c>0and
every x, y Xthere exists an integer n, dependent only on xand y, such that
d(hn(x),h
n(y)) >c. Expansive homeomorphisms exhibit chaotic behavior in that
no matter how close two points are, either their forward or reverse image will even-
tually be a certain distance apart. Plykin’s attractors [4] and the dyadic solenoid
[6] are examples of continua that admit expansive homeomorphisms.
If Uis a collection of open sets, the mesh of Uis defined as mesh(U)=
sup{diam(U):U∈U}.IfUis a finite open cover of continuum X, then the
nerve of Uis a geometric complex N(U) which has a vertex vithat corresponds to
each element Uiof Usuch that hvi1,v
i2, ..., vijiis a simplex of N(U) if and only if
Ui1Ui2... Uij6=. A continuum Xis arc-like if for every >0, there exists a
finite open cover Uwhose mesh is less than and whose nerve is an arc. Arc-like
continua are also called chainable and snake-like continua. A continuum is tree-like
if for every >0, there exists a finite open cover Uwhose mesh is less than and
whose nerve contains no simple closed curves (i.e. a tree-graph). An open cover
whose nerve is a tree is called a tree-cover. Equivalent definitions for a tree-like
continuum, X, are the following:
1) For every >0, there is an onto map g:XTsuch that diam(g1(y)) <
for each yTwhere Tis a tree.
2) X= lim
{Ti,f
i}
i=0.WhereeachTiis a tree and each fi:Ti+1 −→ Tiis a
bonding map.
A continuum is 1-dimensional if for every >0 there exists a finite open cover
Uwhose mesh is less than such that for every yX,yis in at most 2 elements
Received by the editors August 16, 2000 and, in revised form, June 21, 2001.
2000 Mathematics Subject Classification. Primary 54H20, 54F50; Secondary 54E40.
Key words and phrases. Expansive homeomorphism, tr ee-like continua.
The author is pleased to acknowledge the many useful comments and suggestions made by
Charles Hagopian.
c
2002 American Mathematical S ociety
3409
pf3
pf4
pf5

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PROCEEDINGS OF THE AMERICAN MATHEMATICAL SOCIETY Volume 130, Number 11, Pages 3409– S 0002-9939(02)06447-X Article electronically published on May 14, 2002

TREE-LIKE CONTINUA DO NOT ADMIT

EXPANSIVE HOMEOMORPHISMS

CHRISTOPHER MOURON

(Communicated by Alan Dow)

Abstract. A homeomorphism h : X → X is called expansive provided that for some fixed c > 0 and every x, y ∈ X there exists an integer n, dependent only on x and y, such that d(hn(x), hn(y)) > c. It is shown that if X is a tree-like continuum, then h cannot be expansive.

  1. Introduction A continuum is a nondegenerate compact connected metric space. A homeo- morphism h : X → X is called expansive provided that for some fixed c > 0 and every x, y ∈ X there exists an integer n, dependent only on x and y, such that d(hn(x), hn(y)) > c. Expansive homeomorphisms exhibit chaotic behavior in that no matter how close two points are, either their forward or reverse image will even- tually be a certain distance apart. Plykin’s attractors [4] and the dyadic solenoid [6] are examples of continua that admit expansive homeomorphisms. If U is a collection of open sets, the mesh of U is defined as mesh(U) = sup{diam(U ) : U ∈ U}. If U is a finite open cover of continuum X, then the nerve of U is a geometric complex N (U) which has a vertex vi that corresponds to each element Ui of U such that 〈vi 1 , vi 2 , ..., vij 〉 is a simplex of N (U) if and only if Ui 1 ∩^ Ui 2 ∩^ ...^ ∩^ Uij 6 =^ ∅. A continuum^ X^ is^ arc-like^ if for every^  >^ 0, there exists a finite open cover U whose mesh is less than  and whose nerve is an arc. Arc-like continua are also called chainable and snake-like continua. A continuum is tree-like if for every  > 0, there exists a finite open cover U whose mesh is less than  and whose nerve contains no simple closed curves (i.e. a tree-graph). An open cover whose nerve is a tree is called a tree-cover. Equivalent definitions for a tree-like continuum, X, are the following:
  1. For every  > 0, there is an onto map g : X → T such that diam(g−^1 (y)) <  for each y ∈ T where T is a tree.
  2. X = lim←−{Ti, fi}∞ i=0. Where each Ti is a tree and each fi : Ti+1 −→ Ti is a bonding map. A continuum is 1-dimensional if for every  > 0 there exists a finite open cover U whose mesh is less than  such that for every y ∈ X, y is in at most 2 elements

Received by the editors August 16, 2000 and, in revised form, June 21, 2001. 2000 Mathematics Subject Classification. Primary 54H20, 54F50; Secondary 54E40. Key words and phrases. Expansive homeomorphism, tree-like continua. The author is pleased to acknowledge the many useful comments and suggestions made by Charles Hagopian.

© c2002 American Mathematical Society 3409

3410 C. MOURON

of U. A planar continuum X is a non-separating plane continuum provided that R^2 − X is connected. It is important to note that all 1-dimensional non-separating plane continua are tree-like. However, not all tree-like continua can be embedded in the plane. In order for a homeomorphism h to be expansive, h must stretch subcontinua. Since compactness must be preserved, these subcontinua must either be stretched and wrapped or stretched and folded. If a continuum is tree-like, some folding must occur. In this paper, we will see that stretching and folding is not enough to produce an expansive homeomorphism since folding also pushes points closer together. However, stretching and folding is enough to produce continuum-wise expansive homeomorphisms, as there are several examples of arc-like and tree-like continua that admit continuum-wise expansive homeomorphisms [2]. In [3], Kato has shown that arc-like continua do not admit expansive home- omorphisms by first showing that the pseudo-arc does not admit an expansive homeomorphism and then by lifting a homeomorphism of an arc-like continuum to a homeomorphism of the pseudo-arc. Unfortunately, these techniques cannot be extended to tree-like continua. In F.W. Worth’s Dissertation, it was shown that shift homeomorphisms from the inverse limit of tree graphs cannot be expansive homeomorphisms [7], and Kato has also shown that no hereditarily decomposable tree-like continuum can admit an expansive homeomorphism. In the sequel, these results are generalized and it is shown that no tree-like continuum can admit an expansive homeomorphism.

  1. Main results The structure of the proof is as follows:
  1. For purposes of a contradiction, it is assumed that h : X −→ X is an expansive homeomorphism of tree-like continuum X with expansive constant c and let 0 <  < c/3.
  2. A nondegenerate subcontinuum M is found such that diam(hi(M )) → 0 as i → −∞.
  3. For each k, finite sequences {ak^ = xki , ..., xkik = bk} ⊂ M are found such that d(xki , xki+1) < δk and d(ak, bk) < γk, where δk, γk → 0.
  4. For each k, it is shown that there are elements xkα, xkβ ∈ {ak^ = xki , ..., xkik = bk}

such that d(xkα, xkβ ) < γk, d(hi(xkα), hi(xkβ )) <  for all i ≤ 0, and there exists an integer n, 0 ≤ n ≤ k, such that / 3 ≤ d(hn(xkα), hn(xkβ )) < . Let yk = hn(xkα) and

zk = hn(xkβ ).

  1. For each k, it is shown that d(yk, zk) ≥ /3 and d(hi(yk), hi(zk)) <  for all i ≤ k.
  2. Finally, it is shown that there exist limit points y, z of {zk}∞ k=1, {yk}∞ k=1, respectively, such that y 6 = z and d(hi(y), hi(z)) < 2  < c which is a contradiction. The first proposition follows from the Simple Chain Theorem which can be found in most graduate texts such as [5].

Proposition 1. Suppose X is connected and a, b ∈ X. For every  > 0 there exists a finite sequence {xi}ni=1 ⊂ X such that x 1 = a, xn = b, and d(xi, xi+1) < .

The previous sequence is called a simple chain sequence from a to b with mesh less than . The next theorem is due to Kato [2].

3412 C. MOURON

Case 3.  ≤ Qn(xα 1 +1, xβ 1 − 1 ) and xα 1 +1 and xβ 1 − 1 are in same element of T , say T 2. Then W (T 2 , {xi}β α^11 − +1^1 ) = {xα 2 , xβ 2 }, where α 2 < β 2. Suppose T 2 ,... , Tj and xα 2 , xβ 2 ,... , xαj , xβj have been found, again we have 3 cases to consider: Case 1-j. Qn(xαj +1, xβj − 1 ) <  and xαj +1, xβj − 1 are in the same element of T. As in Case 1, this implies that we are done. Case 2-j. xαj +1 and xβj − 1 are not contained in the same element of T. As in Case 2, this implies that we are done. Case 3-j.  ≤ Qn(xαj +1, xβj − 1 ) and xαj +1 and xβj − 1 are in the same element of T , say Tj+1.

Then W (Tj+1, {xi}β i=j^ −α^1 j +1) = {xαj+1 , xβj+1 }, where αj+1 < βj+1, and the induc- tion continues. Eventually, the induction must stop at some j 1. Otherwise, since αj+1 > αj and βj+1 < βj , there would be a j 2 such that |βj 2 − αj 2 | ≤ 1, which would in turn imply Qn(xαj 2 , xβj 2 ) < /6 which is impossible. So if the induction stops at j 1 , then Case 3-j 1 cannot be satisfied. Hence either Case 1-j 1 or Case 2-j 1 must be satisfied and the lemma is satisfied.

Lemma 5. Let h : X −→ X be a homeomorphism of a compact space onto itself. Suppose that there exist sequences {yi}∞ i=1, {zi}∞ i=1 such that d(hk(yn), hk(zn)) <  for all k ≤ n. Then there exists a limit point y of {yi}∞ i=1 and a limit point z of {zi}∞ i=1 such that d(hk(y), hk(z)) < 2  for all k.

Proof. Let Y be the set of limit points of {yi}∞ i=1. Pick y in Y and let {yαi }∞ i=1 be a subseqence that converges to y. Let Zα be the set of limit points of {zαi }∞ i=1. Pick z ∈ Zα and let {zβi }∞ i=1 be a subsequence of {zαi }∞ i=1 that converges to z. Then {yβi }∞ i=1 is a subsequence of {yαi }∞ i=1 and hence also converges to y. For each positive integer n, there exists mn ≥ n such that d(yβmn , y) < L(h, n, /2) and d(zβmn , z) < L(h, n, /2). Thus,

d(hk(y), hk(z)) < d(hk^ (y), hk(yβmn )) + d(hk(yβmn ), hk(zβmn ))

  • d(hk(zβmn ), hk(z)) < /2 +  + / 2

for all −n ≤ k ≤ n. Since n is arbitrary, the lemma holds.

Theorem 6. Tree-like continua do not admit expansive homeomorphisms.

Proof. Suppose that h : X −→ X is an expansive homeomorphism of tree-like continuum X with expansive constant c. Let  be chosen such that 0 <  < c/3. By Theorem 2, there exists a nondegenerate subcontinuum M such that either limn→∞ diam hn(M ) = 0 or limn→−∞ diam hn(M ) = 0. Without loss of generality, we may assume that diam(hi(M )) <  for all i ≤ 0. Let {δk}∞ k=1 be a sequence of positive numbers such that each δk < L(h, k, /6). Let Tk be a tree-cover of X with mesh < δk. Let Ak be any |Tk | + 1 elements of M. By the pigeon-hole principle, for each N , there must be at least 2 elements akN , bkN ∈ Ak such that hN^ (akN ), hN^ (bkN ) are in a common element of Tk. Since Ak is finite, we may conclude that there are two elements ak, bk ∈ Ak and a sequence of increasing integers {Nj }∞ j=1 such that hNj^ (ak) and hNj^ (bk) are in a common element of Tk for each j. Also, since h is expansive, there exists an integer nk such that d(hnk^ (ak), hnk^ (bk)) ≥ c > .

TREE-LIKE CONTINUA 3413

Pick Njk ≥ nk. By Lemma 4, there exists xkα, xkβ ∈ hNjk^ (M ) such that / 3 ≤

QNjk (xkα, xkβ ) <  and d(xkα, xkβ ) < δk. Hence, d(hi(xkα), hi(xkβ )) <  for all i ≤ k. Now, let mk be the positive integer such that d(h−mk^ (xkα), h−mk^ (xkβ )) ≥ /3. Let

yk = h−mk^ (xkα) and zk = h−mk^ (xkβ ). Then d(hi(yk), hi(zk)) <  for all i < k + mk. By Lemma 5, there exist limit points y of {yk}∞ k=1 and z of {zk}∞ k=1 such that d(hi(y), hi(z)) ≤ 2  < c for all i. However, since d(yk, zk) ≥ /3, y and z must be distinct. Therefore, h is not expansive.

A continuum is decomposable if it is the union of two of its proper subcontinuum and indecomposable otherwise. A continuum is hereditarily indecomposable if every subcontinuum is indecomposable.

Question 1 ([3]). Does there exist a hereditarily indecomposable continuum that admits an expansive homeomorphism?

Question 2. Does there exist a non-separating plane continuum that admits an expansive homeomorphism?

If so, then it cannot be 1-dimensional.

References [1] H. Kato, Expansive homeomorphisms in continuum theory, Topology Appl., Proceedings of General Topology and Geometric Topology Symposium, (eds. Y. Kodama and T. Hoshina), 45 (1992), no.3, 223-243. MR 93j: 54023 [2] H. Kato, Continuum-wise expansive homeomorphisms, Can. J. Math. 45 (1993), no. 3, 576-

  1. MR 94k: 54065 [3] H. Kato, The nonexistence of expansive homeomorphisms of chainable continua, Fund. Math. 149 (1996), no. 2, 119-126. MR 97i: 54049 [4] R.V. Plykin, On the geometry of hyperbolic attractors of smooth cascades, Russian Math. Surveys 39 (1974), 85-131. [5] S. Willard, General Topology, Addison-Wesley Publishing Company, Inc., Reading, Mass.,
  2. MR 41: 9173 [6] R.F. Williams, A note on unstable homeomorphisms, Proc. Amer. Math. Soc. 6 (1955), 308-
  3. MR 16:846d [7] F.W. Worth, Concerning the Expansive Property and Shift Homeomorphisms of Inverse Limits, Ph.D. Dissertation, University of Missouri-Rolla, Rolla, Missouri, 1991.

Department of Mathematical Sciences, University of Delaware, Newark, Delaware 19716 E-mail address: mouron@math.udel.edu