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Sociology Chapter two, Study Guides, Projects, Research of Sociology

Sociology Chapter 2 Study Guide

Typology: Study Guides, Projects, Research

2019/2020

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Chapter 2 – Scientific Laws in Chemistry
As chemists, we need a practical way to count atoms and molecules because chemical
processes happen between these particles. Because these particles are so small,
however, we cannot simply count in dozens or other small numbers. In order to simplify
counting and calculations with atoms, we work with moles. The videos of Chapter 2 will
help you learn to determine atomic mass and use atomic mass to convert number of
atoms to moles to mass and vice versa. These skills are essential to understanding the
stoichiometry of chemical reactions.
1. Calculate atomic mass of atoms from the mass and natural abundance of
isotopes
2. Convert between moles and number of atoms
3. Convert between mass and number (in moles)
4. Apply the mole concept to multi-step problems and conversions
Important Scientific Laws in Chemistry
1. Atomic theory grew out of different observations and laws:
A. Conservation of Mass
i. The amount of matter/mass in a chemical reaction stays constant
throughout the process; it is neither created nor destroyed
ii. “in a chemical reaction, matter is neither created nor destroyed”
1. If you can account for everything before and after a reaction, the
mass will be the same
iii. what happens to the gasoline we burn driving?
1. 2C8H18 + 25 O2 = 16 CO2 + 18 H2O
iv. Gasoline burns to form carbon dioxide and water
v. Total mass of the substances involved in a reaction does not change
vi. the atoms rearrange, but do not disappear. Mass is conserved
B. Conservation of Energy
i. Energy is neither created nor destroyed, though it can change forms.
Total energy stays constant.
C. Definite proportions and multiple proportions
i. Definite proportions
1. “All samples of a given compound, regardless of their source or how
they were prepared, have the same proportions of their constituent
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Chapter 2 – Scientific Laws in Chemistry As chemists, we need a practical way to count atoms and molecules because chemical processes happen between these particles. Because these particles are so small, however, we cannot simply count in dozens or other small numbers. In order to simplify counting and calculations with atoms, we work with moles. The videos of Chapter 2 will help you learn to determine atomic mass and use atomic mass to convert number of atoms to moles to mass and vice versa. These skills are essential to understanding the stoichiometry of chemical reactions.

  1. Calculate atomic mass of atoms from the mass and natural abundance of isotopes
  2. Convert between moles and number of atoms
  3. Convert between mass and number (in moles)
  4. Apply the mole concept to multi-step problems and conversions Important Scientific Laws in Chemistry
  5. Atomic theory grew out of different observations and laws: A. Conservation of Mass i. The amount of matter/mass in a chemical reaction stays constant throughout the process; it is neither created nor destroyed ii. “in a chemical reaction, matter is neither created nor destroyed”
  6. If you can account for everything before and after a reaction, the mass will be the same iii. what happens to the gasoline we burn driving?
  7. 2C8H18 + 25 O2 = 16 CO2 + 18 H2O iv. Gasoline burns to form carbon dioxide and water v. Total mass of the substances involved in a reaction does not change vi. the atoms rearrange, but do not disappear. Mass is conserved B. Conservation of Energy i. Energy is neither created nor destroyed, though it can change forms. Total energy stays constant. C. Definite proportions and multiple proportions i. Definite proportions
  8. “All samples of a given compound, regardless of their source or how they were prepared, have the same proportions of their constituent

elements.” A. The mass ratio of oxygen to hydrogen will always be the same no matter where the water come from. B. Mass ratio in a sample of water: 16.0 g O/2.0 g H = 8.0 or 8:

  1. Multiple Proportions A. “when two elements (A and B) form two or more different compounds, the masses of element B that combine with 1 g of element A can be expressed as a ratio of small whole numbers.” B. Carbon monoxide : “AB” C. Carbon dioxide: “AB2” D. Two different compounds containing osmium (Os) and oxygen (O) have the following masses of oxygen per gram of osmium: 0. g and 0.3369g. Show that these amounts are consistent with the law of multiple proportions. i. Compound 1 0.168 g O : 1.000 g Os ii. Compound 2 0.3369 g O : 1.000 g Os iii. Compound 2 O Mass/compound 1 O Mass = 0.3369g/0.168g = 2.005 ~=~ 2 E. Fun Fact: osmium is the densest natural element, more than twenty times denser than water, and 1 kg costs $13, Atomic Theory
  2. Dalton’s Atomic Theory – 1808 A. John Dalton sets out to explain the laws with his atomic theory: i. Atoms are small, indestructible particles that make elements ii. All atoms of a given element have same mass and properties iii. Atoms combine in whole-number ratios, to make molecules iv. Atoms of one element can’t change into atoms of another
  3. Atom A. Atoms: smallest unit of elements and the subunit of molecules. i. From the Greek atomos meaning “that which can not be split” B. Atoms themselves are made of smaller pieces: i. Central nucleus, containing protons and neutrons ii. Electrons that orbit the nucleus

D. Smallest factor? Let’s pretend we did this experiment. We determine the charge on four different oil drops: i. -3.2 x 10^-19 C ; -6.4 x 10^-19C ; -12.8 x 10^-19C ; -1.6 x 10^-19C ii. We know there much be a whole number of electrons, so we can assume some whole number factor. To find it, we will divide each number by the smallest charge we found: iii. =2 =4 =8 = iv. Based on this, we would find that the factor is -1.6x10^-19 C, and that is the charge of a single electron

  1. Mass of the Electron A. We have a couple of pieces of the e^- puzzle now: i. Charge-to-mass ratio: -1.76x10^8 C/g ii. Charge of an electron: -1.60 x 10^-19 C B. What’s the mass of a ratio? i. Charge * (mass/charge) = mass ii. -1.60 x 10^-19 C * (1g/-1.76x10^8C) = 9.10 x 10^-28g iii. An electron is around 2000 times lighter than a hydrogen atom
  2. Structure of the Atom – “Plum-pudding” A. Thomson suggests a “plum-pudding” model of the atom i. The atom is a sphere of positive charge with small e^- moving through it B. Radioactivity discovered, more subatomic particles are observed i. Alpha, beta, and y particles coming from the core of large, radioactive atoms C. Ernest Rutherford sets out to confirm Thomson’s theory in 1909
  3. Discovery of the Nucleus – 1909 A. Rutherford shoots positive alpha particles at a thin sheet of gold foil i. With plum-pudding model, expected that alpha particles pass right through B. The results are shocking. The alpha particles are deflected! i. The particles are hitting something on the way through the foil C. The alpha particles are deflecting off small, heavy nucleus in the atom. D. Rutherford develops nuclear theory to explain this new model:

i. Most of the atom’s mass and all its positive charge is in the nucleus at the center of the atom ii. Most of the volume of an atom is empty, and e^- are dispersed here iii. # p^+ = # e^-, so the atom is overall electrically neutral

  1. Neutrons – 1932 A. Protons are positively charged particles in the nucleus B. Neutrons are confirmed by James Chadwick, explaining the additional mass in the nucleus i. Why is helium 4x heavier than hydrogen if it only has one p^+?
  2. Because the subatomic of neutron has same mass as the proton The Scale of the Atom
  • Atoms are really small. So small that using our SI units with them becomes difficult  Table: masses of Subatomic Particles in Kilograms Particle Symbol Mass Proton P^+ 1.67262x10^-27 kg Neutron N^0 1.67493x10^-27 kg Electron E^- 0.00091x10^-27 kg
  • Because of this, we use a special unit called an atomic mass unit (amu). Technically, 1 amu is 1/12th of the mass carbon-12 atom (which has 6 protons, 6 neutrons and 6 electrons). But that works out to protons and neutrons having a mass of about 1 amu each, and an electron having a mass of 0.00055 amu^- practically zero.  Table: Masses of Subatomic Particles in Atomic Mass Units Particle Charge Relative Proton P^+ 1 amu Neutron N^0 1 amu Electron E^- 0 amu
  • Remember that the charge of an electron is -1.60x10^-19 Coulombs. Since protons and electrons have an equal and opposite charge, the charge of a proton is +1.60x10^-19 C. To simplify things further, we use relative charge in chemistry. An electron has a charge of -1 and a proton has a charge of +1. Neutrons are neutral and don’t have an electrical charge  Table: charges of Subatomic particles Particle Charge Relative

44+56 = 100; chemical symbol: Ru^4+

  1. Given: Iodine-131; Chemical symbol – I^- A. Atomic number: 53; protons: 53; mass number: 131; neutrons: 131-53 = 78; electrons: 54
  2. Given: Mg^2+; neutrons – 13 A. Isotope name: magnesium-25; atomic number: 12; protons: 12; mass number 12+13 = 25; electrons: 10 Average Atomic Mass
  • The natural abundance of isotopes is used with their atomic masses to calculate an average atomic mass. We find the average atomic mass on the periodic table (hydrogen’s is 1.008 amu). Because we often deal with huge numbers of atoms, its beneficial to use the averaged mass that accounts for the different isotopes of the element.
  • Chlorine has two naturally occurring isotopes: 75.78%^35Cl(34.97 amu) and 24.22%^37Cl (36.97 amu). To find the average atomic mass of chlorine, we take a weighted average of all the isotopes according to their abundances. According to the periodic table, the average atomic mass of chlorine is 35.45 amu.
  • Average Atomic mass = sum (fraction of isotope n) x (mass of isotope n)  Sum is a summation symbol, meaning to add up all (fraction of isotope n) x (mass of isotope n) together.  Average atomic mass of  Cl = (0.7578) x (34.97 amu) + (0.2422) x (36.97 amu) = 35.45 amu Video: How to Calculate Atomic Mass Practice Problems
  1. Gallium has two stable isotopes, and the masses of Gallium-69 (60.11% abundant) and Gallium-71 (39.89% abundant) are 68.926 amu and 70.925 amu, respectively. Calculate the average atomic mass of Gallium A. (68.926 x 0.6011) + (70.925 x 0.3989) = 69.72 amu
  2. Rubidium has two isotopes: Rubidium-85 (atomic mass of 84.911 amu) and Rubidium-87 (86.909 amu). The atomic weight of Rubidium reported on the periodic table is 85.47. Based on this information, which of the isotopes of Rubidium is more abundant? How do you know? A. Rubidium-85 is more abundant because weight average is closer to 85 amu which is the atomic mass of Rubidium-
  3. Magnesium has three stable isotopes. Calculate its average atomic mass, using the information in the chart below Isotope Mass Abundance

Magnesium-24 23.985 amu 78.99% Magnesium-25 24.986 amu 10.00% Magnesium-26 25.983 amu 11.01% A. (23.985 x 0.7899) + (24.986 x 0.1000) + (25.983 x 0.11.01) = 24.31 amu Ions

  • Atoms can also gain and lose electrons. When an atom gains or loses electrons, the number of protons no longer equals the number of electrons. This results in an ion which is positively or negatively charged.  If an atom loses electrons, a cation is formed with a positive charge.  Neutral lithium, Li0, has 3 protons and 3 electrons. L^+ is a cation, with 3 protons and only 2 electrons. Because there is one more proton than there are electrons, the ion has an overall +1 charge.  If an atom gains electrons, an anion is formed with a negative charge.  Neutral fluorine, F^0, has 9 protons and 9 electrons. F^- is an anion, with 9 protons and 10 electrons. Because there is one more electron than there are protons, the ion has an overall -1 charge.
  • Because of their different electric charge, ions have much different properties when compared to their neutral atoms. We will delve deeper into ionic species, but you may use the table below to predict common ions formed from the elements. The Periodic Table
  • Chemical symbols are assembled on the periodic table, giving chemists an organized view of the elements. The periodic table dates back to the late 1800s and the work of Dmitri Mendeleev, who set down the periodic law: “When the elements are arranged in order of increasing mass, certain sets of properties recur periodically.”

Groups on the Periodic Table

  • The many groups and “blocks” of the periodic table have names to further define certain elements. The common ones we will focus on in class are the alkali metals, alkaline earth metals, transition metals, halogens and noble gases.
  1. The Alkali metals are the first column of the periodic table (excluding hydrogen). Including lithium, sodium and potassium, these metals are very reactive and even explode on contact with water.
  2. The alkaline earth metals are the second column of the periodic table. Including magnesium and calcium, these metals are also very reactive, but not to the same degree as the alkali metals.
  3. The transition metals occupy the center of the periodic table. Containing elements like iron and gold, these elements have different properties from the rest of the elements in the “main group.” There properties vary widely, and they are not a focus of Chemistry 1A.
  4. The halogens occupy the second to last column of the periodic table. Including fluorine, chlorine and bromine, these elements are very reactive and corrosive. Chlorine, for instance, is infamous for its use in chemical warfare during World War One.
  5. The noble gases are in the last column. Containing the elements helium and neon, they are characterized by being very nonreactive and stable. Video: The periodic table – classification of elements
  6. Groups: vertical column 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

A. 1A 2A 3A 4A 5A 6A 7A 8A

  1. Periods: horizontal row: 1 2 3 4 5 6
  2. Alkali metals: 1 or 1A except Hydrogen(non-metals); react with water;
  3. Alkaline earth metals: 2A; reactive (not reactive as 1A but still.);
  4. Metals: group 3~12; heat, electricity
  5. Nonmetals: hydrogen A. Halogens: 7A; very reactive, often powerful, aggressive; B. Noble gases: 8A; colorless; generally unreactive
  6. Metalloids: between metals and nonmetals; B, Si, Ge, As, Sb, Te, At,(At is depends on the textbook); semi-conductors More Concept – Counting atoms by the gram Video: the mole and Avogadro’s number
  7. Average atomic mass – masses of samples
  8. Ex) Lithium: 6.94 u/atomli ----- x certain # of atoms ----- 6.94 g Li A. 6.02214076x10^23 ~~ 6.022x10^23 : Avogadro’s number
  9. Moles? Dozen; I have a dozen of eggs = 12 eggs ; I have a mole of Lithium = 6.022x10^23 Lithium mole
  10. Changing moles to atoms A. Ex: 15.4 mg Ge => 15.4 mg Ge * (1 g Ge/ 1000 mg Ge) * (1 mol Ge/ 72.63 g Ge) * (6.022x10^23 atoms Ge/ mole Ge) = 1.28 x 10^20 atoms Ge