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Sine/Cosine Graphs - Examples with Resolution | MATH 117, Study notes of Trigonometry

Material Type: Notes; Professor: Neal; Class: TRIGONOMETRY; Subject: Mathematics (Univ); University: Western Kentucky University; Term: Spring 2009;

Typology: Study notes

Pre 2010

Uploaded on 08/17/2009

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Dr. Neal, Spring 2009
MATH 117 Sine/Cosine Graphs
Each trigonometric function can be graphed as a function of
x
, where the variable
x
is
always in radians. In particular, the functions y=sinx and
y=cos x
are defined for all
x
and are cyclic. That is, the shape of the graph repeats itself over the periods
. . . .
4π≤ x≤−2π
2π≤ x0
0x2π
2π≤ x4π
4π≤ x6π
. . . etc.
which are simply wrap-arounds of the unit circle.
The Sine Graph
One cycle of the sine graph occurs as
x
ranges from 0 to 2π (radians), and the shape of
the graph can be molded around the values occuring at
x
= 0, π
2
, π, 3π
2
, and 2π.
x
0π
2
π
3π
2
2π
ysinx010–1 0
1
–1
2π
π
2
π3π
2
1
–1
2π
–2π
One Cycle of ysinxTwo Cycles
Multiplying by a negative reflects the graph about the
x
-axis and multiplying by a
constant “
a
” increases the range to –
a
y
a
rather than –1
y
1.
2π
4
–4
π
3
–3
2π
π/2
One Cycle of y4sinx
Amplitude = 4 One Cycle of y3sinx
Amplitude = |–3| = 3
pf3
pf4
pf5

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MATH 117 Sine/Cosine Graphs

Each trigonometric function can be graphed as a function of x , where the variable x is always in radians. In particular, the functions y = sin x and y = cos x are defined for all x and are cyclic. That is, the shape of the graph repeats itself over the periods

.... − 4 π ≤ x ≤ − 2 π − 2 π ≤ x ≤ 0 0 ≤ x ≤ 2 π 2 π ≤ x ≤ 4 π 4 π ≤ x ≤ 6 π... etc.

which are simply wrap-arounds of the unit circle.

The Sine Graph

One cycle of the sine graph occurs as x ranges from 0 to 2π (radians), and the shape of

the graph can be molded around the values occuring at x = 0, π 2

, π, 3 π 2

, and 2π.

x (^) 0

π 2 π^

3 π 2 2 π

y sin x^0 1 0 –1^0

π 2 π 2

π 3 π 2

–2π 2 π

One Cycle of y sin x Two Cycles

Multiplying by a negative reflects the graph about the x -axis and multiplying by a constant “ a ” increases the range to – aya rather than –1 ≤ y ≤ 1.

2 π

π

π/2^2 π

One Cycle of y 4sin x Amplitude = 4

One Cycle of y 3sin x Amplitude = |–3| = 3

Phase Shift

Given the graph of y = f ( x ) , we can shift the graph to the right by c units with the function y = f ( xc ). We shift to the left c units with the function y = f ( x + c ).

(^3) – y = x^2 y = ( x − 3)^2 shifts x^2 to the right by 3

y = ( x + 2)^2 shifts x^2 to the left by 2

Similarly, we can shift the sine graph to the left or right by a certain angle with the function y = a sin( x ± c ). ––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––––

Example 1. Graph one cycle each of the following functions. Label five points on the x - axis that show where the roots and the peaks occur.

(a) y = 2sin x + π 3

^

^ (b)^ y^ = −3sin^ x^ −

π 4

^

Solution. (a) The sine graph is shifted to − π 3

, where one cycle begins. One cycle ends

after length 2 π which is at − π 3

  • 2 π = − π 3

6 π 3

5 π 3

. So now divide the cycle length of

2 π into 4 equal pieces of length 2 π 4

π 2

. To do so, we must add lengths of π 2

from the

starting point of − π 3

. That is, start at − 2 π 6

and start adding 3 π 6

Start at − 2 π 6

Add 3 π 6

Add 3 π 6

Add 3 π 6

Add 3 π 6 − π 3

2 π 6

π 6

4 π 6

2 π 3

7 π 6

10 π 6

5 π 3 2

π 6

7 π 6

5 π 3

2 π 3

− π 3

y = 2sin x + π 3

^

π

π 2

5 π 2

2 π

π

y 2cos x Amplitude = 2

One Cycle of y 5cos x Amplitude = |–5| = 5

Example 2. Graph one cycle each of the following functions. Label five points on the x - axis that show where the roots and the peaks occur.

(a) y = 3cos x − π 6

^

^ (b)^ y^ = −4cos^ x^ +

π 8

^

Solution. (a) The cosine graph is shifted to + π 6

, where one cycle begins. Divide the

cycle length of 2 π into 4 equal pieces of length 2 π 4

3 π 6

, and add these lengths of 3 π 6

from the starting point of π 6

Start at π 6

Add 3 π 6

Add 3 π 6

Add 3 π 6

Add 3 π 6 π 6

4 π 6

2 π 3

7 π 6

10 π 6

5 π 3

13 π 6

π 6

2 π 3

7 π 6

13 π 6

5 π 3

y = 3cos x − π 6

^

(b) The negative cosine graph is shifted to − π 8

, where one cycle begins. Divide the

cycle length of 2 π into 4 equal pieces of length 2 π 4

4 π 8

, and add these lengths of 4 π 8

from the starting point of − π 8

Start at − π 8

Add 4 π 8

Add 4 π 8

Add 4 π 8

Add 4 π 8 − π 8

3 π 8

7 π 8

11 π 8

15 π 8

− π 8

3 π 8

7 π 8

11 π 8

15 π 8

y = −4cos x + π 8

^