Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Quiz: 8 Questions on Introduction to Chemical Principles - Solutions | CHEM 40, Quizzes of Chemistry

Material Type: Quiz; Class: Intro to Chemical Principles; Subject: Chemistry; University: City College of San Francisco; Term: Fall 2008;

Typology: Quizzes

Pre 2010

Uploaded on 08/17/2009

koofers-user-pyv
koofers-user-pyv 🇺🇸

10 documents

1 / 1

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Chemistry 40 Name______________________________
Quiz 4, Fall 08
1.) Complete the following table. (3points)
Acid Base Conjugate Acid Conjugate Base
H2O NH3 NH4+ HO-
HCl H2O H3O+ Cl-
H2SO4 NaOH H2O HSO4-
2.) What is the molarity of a 200ml solution containing 4.2 g of NaCl? (3 points)
Molar Mass of NaCl = 58.443g moles of NaCl = 4.2g / 58.433g = .072 moles
Molarity (M) = moles (n)/ volume (L) = .072 / 200 x 10-3 = .36M
3.) What is the concentration of potassium ions in a 1.4M solution of K2SO4? (2 points)
K2SO4 = 2K+ + SO42-
1.4M x 2 = 2.8M
5.) What is the pH of a 10 - 3 M solution of HCl? (2 points)
pH = 3
6.) What is the [H+] of a solution given pOH = 3.28 (2 points)
pH + pOH = 14
pH = 14 – 3.28 = 10.72
[H+] = 1.9 x 10-11
7.) Calculate the pH of a 40 ml solution containing 1.00 g of nitric acid. (3 points)
Nitric acid = HNO3 HNO3 = H+ + NO3-
Molar Mass of HNO3 = 63.012g moles of HNO3 = 1.00g / 63.012g = .0159 moles
Molarity (M) = moles (n)/ volume (L) = .0159 / 40 x 10-3 = .398M
8.) How many ml of a 0.2 M NaOH solution are required to bring the pH of 20 ml of a 0.4 M HCl solution
to 7.0? (5 points)
At pH = 7 [H+] = [OH-]
Molarity (M) = moles (n)/ volume (L) moles of HCl = 0.4M x 20x10-3 = .008 = moles of NaOH needed
Volume (L) = .008 moles of NaoH / 0.2M = .04 L or 40 ml

Partial preview of the text

Download Quiz: 8 Questions on Introduction to Chemical Principles - Solutions | CHEM 40 and more Quizzes Chemistry in PDF only on Docsity!

Chemistry 40 Name______________________________ Quiz 4, Fall 08 1.) Complete the following table. (3points) Acid Base Conjugate Acid Conjugate Base H 2 O NH 3 NH 4 +^ HO - HCl H 2 O H 3 O +^ Cl- H 2 SO 4 NaOH H 2 O HSO 4 -

2.) What is the molarity of a 200ml solution containing 4.2 g of NaCl? (3 points) Molar Mass of NaCl = 58.443g moles of NaCl = 4.2g / 58.433g = .072 moles Molarity (M) = moles (n)/ volume (L) = .072 / 200 x 10 -3^ = .36M 3.) What is the concentration of potassium ions in a 1.4M solution of K 2 SO 4? (2 points) K 2 SO 4 = 2K+^ + SO 4 2- 1.4M x 2 = 2.8M 5.) What is the pH of a 10 - 3^ M solution of HCl? (2 points) pH = 3 6.) What is the [H +] of a solution given pOH = 3.28 (2 points) pH + pOH = 14 pH = 14 – 3.28 = 10. [H +] = 1.9 x 10- 7.) Calculate the pH of a 40 ml solution containing 1.00 g of nitric acid. (3 points) Nitric acid = HNO 3 HNO 3 = H +^ + NO 3 - Molar Mass of HNO 3 = 63.012g moles of HNO 3 = 1.00g / 63.012g = .0159 moles Molarity (M) = moles (n)/ volume (L) = .0159 / 40 x 10 -3^ = .398M

8.) How many ml of a 0.2 M NaOH solution are required to bring the pH of 20 ml of a 0.4 M HCl solutionto 7.0? (5 points)

At pH = 7 [H +] = [OH -^ ] Molarity (M) = moles (n)/ volume (L) moles of HCl = 0.4M x 20x10 -3^ = .008 = moles of NaOH needed Volume (L) = .008 moles of NaoH / 0.2M = .04 L or 40 ml