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Notes on Linear Functional and The Algebraic Conjugate Space | MATH 3912, Study notes of Mathematics

Material Type: Notes; Class: Junior Seminar; Subject: Mathematics; University: Seton Hall University; Term: Spring 2004;

Typology: Study notes

Pre 2010

Uploaded on 08/08/2009

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Linear Functionals and the Algebraic Conjugate
Space
Kerri Pisano
February 23, 2004
In many problems, we must associate a number with a function extracted
from a given class of functions. For example:
to each function f(x) that has a continuous derivative on [a, b], we may
want to associate the number Rb
a(1 + [f0(x)]2)1
2dx.
to each function f(x, y) that is twice continuously differentiable over a
closed bounded region B, we may have to form the number
R RB(∂f
∂x )2+ ( ∂f
∂y )2dxdy
for the same function as above we associate, more simply, f(x0, y0) where
(x0, y0)B.
Such an association is known as a functional.
Definition 0.1 Let Xbe a linear vector space and to each xlet there be asso-
ciated a unique real (or complex) number designated by L(x). If for x, y X
and for all real (or complex) α, β we have
L(αx +βy) = αL(x) + β L(y),
then Lis called a linear functional over X.
Example 0.1 X=C[a, b], i.e. the elements of Xare continous functions f(x).
We define Las
L(f) = Zb
a
f(x)dx
.
To show this is a linear functional we must verify it is a functional and it is
linear.
To see that it is a functional is easy: if fC[a, b] then fis continous
and therefore integrable over the interval [a, b]. Therefore the integral L(f) =
Rb
af(x)dx exists, so that Lassociates to every element fa number.
1
pf3

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Linear Functionals and the Algebraic Conjugate

Space

Kerri Pisano

February 23, 2004

In many problems, we must associate a number with a function extracted from a given class of functions. For example:

  • to each function f (x) that has a continuous derivative on [a, b], we may want to associate the number

∫ (^) b a (1 + [f^

′(x)] (^2) ) 12 dx.

  • to each function f (x, y) that is twice continuously differentiable over a closed bounded region∫ ∫ B, we may have to form the number B (^

∂f ∂x )

(^2) + ( ∂f ∂y )

(^2) dxdy

  • for the same function as above we associate, more simply, f (x 0 , y 0 ) where (x 0 , y 0 ) ∈ B.

Such an association is known as a functional.

Definition 0.1 Let X be a linear vector space and to each x let there be asso- ciated a unique real (or complex) number designated by L(x). If for x, y ∈ X and for all real (or complex) α, β we have

L(αx + βy) = αL(x) + βL(y),

then L is called a linear functional over X.

Example 0.1 X = C[a, b], i.e. the elements of X are continous functions f (x). We define L as

L(f ) =

∫ (^) b

a

f (x)dx

.

To show this is a linear functional we must verify it is a functional and it is linear.

To see that it is a functional is easy: if f ∈ C[a, b] then f is continous and therefore integrable over the interval [a, b]. Therefore the integral L(f ) = ∫ (^) b a f^ (x)dx^ exists, so that^ L^ associates to every element^ f^ a number.

To show that it is linear we need to verify that for two functions f and g in C[a.b] we have L(αx + βy) = αL(x) + βL(y):

L(αf + βg) =

∫ (^) b

a

αf (x) + βg(x)dx =

∫ (^) b

a

αf (x)dx +

∫ (^) b

a

βg(x)dx =

= α

∫ (^) b

a

f (x)dx + β

∫ (^) b

a

g(x)dx =

= αL(f ) + βL(g)

which finishes the proof.

Example 0.2 Let X = C[a, b] be as before but this time define define L as:

L(f ) =

∫ (^) b

a

x^2 f (x)dx

.

It is easy to see - similar to above - that L is again a functional as well as linear.

Example 0.3 X = C^2 [a, b].

L(f ) = f ′′(a) + f ′(b) − f ( a + b 2

Interpolation theory is concerned with reconstructing functions on the basis of certain functional information assumed known. In many cases, the functionals are linear. Functionals can be added to one another and scalar products can be formed. If, for instance, f ∈ C^1 [a, b] and

L 1 (f ) =

∫ (^) b

a

f (x)dx and L 2 (f ) = f ′( a + b 2

we can identify the functional

L(f ) = α

∫ (^) b

a

f (x)dx + βf ′(

a + b 2

with the expression αL 1 + βL 2. L is itself a linear functional.