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Natural Numbers - Abstract Algebra - Assignment 4 | MATH 411, Assignments of Abstract Algebra

Material Type: Assignment; Professor: Howard; Class: Abstract Algebra; Subject: Mathematics; University: Eastern Michigan University; Term: Spring 2009;

Typology: Assignments

Pre 2010

Uploaded on 09/17/2009

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Math 411 Spring 2009 May 4 Problems
Section 1.1, page 14, problems 1.1, 1.2 and 1.20
1.1 True or false with reasons.
(i) There is a largest integer in every nonempty set of negative integers.
(ii) There is a sequence of 13 consecutive natural numbers containing exactly 2 primes.
(iii) There are at least two primes in any sequence of 7 consecutive natural numbers.
(iv) Of all the sequences of consecutive natural numbers not containing 2 primes there is a sequence of shortest
length.
(v) 79 is a prime.
(vi) There exists a sequence of statements S(1), S(2), . . . with S(2n) true for all n1 and with S(2n1) false
for every n1.
(vii) If mand nare natural numbers, then (mn)! = m!n!.
1.2 (i) For any n0 and any r6= 1, prove that
1 + r+r2+···+rn=1rn+1
1r.
(ii) Prove that
1 + 2 + 22+· · · + 2n= 2n+1 1
(for all natural numbers n).
1.20 Prove that 4n+1 + 52n1is divisible by 21 for all n1.

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Math 411 Spring 2009 May 4 Problems

Section 1.1, page 14, problems 1.1, 1.2 and 1.

1.1 True or false with reasons. (i) There is a largest integer in every nonempty set of negative integers. (ii) There is a sequence of 13 consecutive natural numbers containing exactly 2 primes. (iii) There are at least two primes in any sequence of 7 consecutive natural numbers. (iv) Of all the sequences of consecutive natural numbers not containing 2 primes there is a sequence of shortest length. (v) 79 is a prime. (vi) There exists a sequence of statements S(1), S(2),... with S(2n) true for all n ≥ 1 and with S(2n − 1) false for every n ≥ 1. (vii) If m and n are natural numbers, then (mn)! = m!n!. 1.2 (i) For any n ≥ 0 and any r 6 = 1, prove that

1 + r + r^2 + · · · + rn^ =^1 −^ r

n+ 1 − r. (ii) Prove that 1 + 2 + 2^2 + · · · + 2n^ = 2n+1^ − 1 (for all natural numbers n). 1.20 Prove that 4n+1^ + 5^2 n−^1 is divisible by 21 for all n ≥ 1.