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Midterm Exam MA140-01 Calculus Questions - Prof. Paula R. Stickles, Exams of Calculus

A midterm exam for a calculus course, with various calculus-related questions covering limits, derivatives, integrals, and asymptotes. Students are expected to use the definition of derivatives, limits, and long division of polynomials to solve the problems.

Typology: Exams

Pre 2010

Uploaded on 08/04/2009

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MA140-01
3/4/09
Page 1
Midterm Exam
Calculator Portion
Will the real ________________________ please stand up?
1.) Let
3
( )
5
f x
x
=
. Using the definition of the derivative, find
'( ).
f x
6 points
0 0
3 3
( ) ( )
5 5
lim lim
h h
f x h f x x h x
h h
+
0
3( 5) 3( 5)
( 5)( 5)
lim
h
x x h
x h x
h
+
+
0
3 15 3 3 15
( 5)( 5)
lim
h
x x h
x h x
h
+
+
0
3
( 5)( 5)
lim
h
h
x h x
h
+
2
0
3 3
lim
( 5)( 5) ( 5)
h
x h x x
+
2.) Given
>+
=1
13
)(
2
xifkx
xifkx
xf
. Find the value of k such that
( )
f x
is continuous
everywhere. 4 points
The two pieces of the function are polynomials, so they are continuous everywhere. The only concern is at the breaking
point of x =-1. For f to be continuous at -1, the left and right side limits must be equal so that the limit exists.
( 1) ( 1) 3 3
f k k
= =
2
1 1
lim ( ) lim [( 1) ] 1
x x
f x k k
+ +
→− →−
= + +
1 1
lim ( ) lim [ ( 1) 3] 3
x x
f x k k
→− →−
=
Setting the left and right-side limits equal gives the following.
1 3
k k
+ =
2 4 2
k k
= =
3.)
Suppose that
<
=
<<
=
<<+
=
424
20
20
02
021
)(
xx
x
xx
x
xx
xf .
8 points
(a) Determine
2
lim ( )
x
f x
+
→−
. (c) Determine )(lim
0
xf
x
.
-1 DNE
(b) Determine )(lim
2
xf
x
. (d) Determine
4
lim ( )
x
f x
.
-2 0
pf3
pf4

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Download Midterm Exam MA140-01 Calculus Questions - Prof. Paula R. Stickles and more Exams Calculus in PDF only on Docsity!

3/4/

Page 1

Midterm Exam Calculator Portion

Will the real ________________________ please stand up?

1.) Let 3

f x

x

. Using the definition of the derivative, find (^) f '( ). x 6 points

0 0

lim lim h h

f x h f x (^) x h x

→ (^) hh

0

lim h

x x h

x h x

h

0

lim h

x x h

x h x

h

0

lim h

h

x h x

h

0 2

lim h → ( x h 5)( x 5) ( x 5)

2.) Given



2 x k if x

kx if x f x. Find the value of k such that (^) f ( ) x is continuous

everywhere. 4 points

The two pieces of the function are polynomials, so they are continuous everywhere. The only concern is at the breaking

point of x =-1. For f to be continuous at -1, the left and right side limits must be equal so that the limit exists.

f ( 1)− = k ( 1)− − 3 = − k − 3 2

1 1

lim ( ) lim [( 1) ] 1 x x

f x k k →− +^ →−+

1 1

lim ( ) lim [ ( 1) 3] 3 x x

f x k k →− −^ →−−

Setting the left and right-side limits equal gives the following.

1 + k = − k − 3

2 k = − 4 → k = − 2

3.) Suppose that

x x

x

x x

x

x x

f x. 8 points

(a) Determine 2

lim ( ) x

f x →−+

. (c) Determine lim ( ) 0

f x x

-1 DNE

(b) Determine lim ( ) 2

f x x

. (d) Determine 4

lim ( ) x

f x →−

3/4/

Page 2

4.) Determine all vertical, horizontal, and slant asymptotes where they apply for 2 3 4 ( ). 5 1

x x f x x

  • − = −

Label the asymptotes. 4 points

Vertical asymptote at

x =

No horizontal asymptotes

Slant asymptote at

y = x + (Use long division of polynomials.)

5.) A spherical balloon is expanding. If the radius is increasing at the rate of 2 inches per minute, at what

rate is the volume increasing when the radius is 5 inches? 5 points

(^43)

3

V = π r

(^42) 3 3

dV dr r dt dt

π

 



(^42) 3 (5) (2) 3

dV

dt

π

 



(^42) 3 (5) (2) 3

dV

dt

π

 



3 3 200 in / m in 628.32in / m in

dV

dt

= π ≈

6.) Use logarithmic differentiation to find the derivative of

co s

x

f x = x.^ 5 points

cos ( )

x f x = x

[ ]

co s ln ( ) ln x f x =  x 

ln [ f ( x ) ] =(cos x ) ln[ x ]

[ ]

1 1 '( ) ( sin )(ln ) (c o s ) ( )

f x x x x f x x

= − +

1 f '( x ) ( s in x )(ln x ) (c o s x ) f ( x ) x

  = (^) − + ⋅

(^1) c o s '( ) ( s in ) (ln ) ( c o s ) x f x x x x x x

  = − + ⋅ 

7.) Use the Squeeze Theorem to determine the following limit. 4 points

4 0 6

lim sin x

x → (^) x

6

1 sin 1 x

4 4 4 6

x x sin x x

4 4 4 0 0 6 0

lim lim sin lim x x x

x x x → → (^) x

4 4 0 6 0 6

0 lim sin 0, which means lim sin must be 0. x x

x x → (^) xx

3/4/

Page 4

10.) The graph of y = f ( ) x is given below. From this graph, sketch a graph of y = f '( ) x on the

same set of axes. 4 points

11.) Determine coefficients a, b, and c so that the curve f(x) = ax

2

  • bx + c will pass

through the point (1,3) and line 4x + y = 8 is tangent to the curve at the point (2, 0).

Since f ( ) x passes through (1,3) and (2,0), both points must satisfy the function. This results in

two equations.

2 3 = a (1) + b (1) + c  a + b + c = 3

2 0 = a (2) + b (2) + c  4 a + 2 b + c = 0

Since the line 4 x + y = 8 is tangent to the curve at (2,0), its slope must be the same as the

derivative of the function at x=2. (The slope of the line is -4.) This results in a third equation.

f '( ) x = 2 ax + b and at x = 2 with the slope of the tangent line equal to 4, the resulting equation is 4 a + b = −4.

So,

a + b + c = 3

4 a + 2 b + c = 0

4 a + b = − 4

Working with the first two equations, you can eliminate variable c. Multiply the first equation by

-1 and add the two equations together. This result in the new equation of 3 a + b = − 3. Working

with this new equation and third equation, you can eliminate another variable. [I’m choosing b.

You can multiply either equation by -1 and then add them together. This results in...

a = − 1

Now, work backwards. If a = − 1 , then b = 0 ,which means c = 4.