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The liate method is a rule for integration by parts, helping to determine which function should be used as u and dv. Examples and exceptions to the liate rule. Tabular integration by parts is an alternative method for recursive integration by parts.
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The LIATE method was first mentioned by Herbert E. Kasube in [1]. The function that appears first in the following list should be u when using integration by parts:
L Logatithmic functions ln(x), log 2 (x), etc. I Inverse trig. functions tan−^1 (x), sin−^1 (x), etc. A Algebraic functions x, 3x^2 , 5x^25 , etc. T Trig. functions cos(x), tan(x), etc. E Exponential functions ex, 2x, etc.
Example 1. ∫ x sin(x)dx.
Following the LIATE method, u = x and dv = sin(x)dx since x is an algebraic function and sin(x) is a trigonometric function. Therefore,
u = x dv = sin(x)dx du = dx v = − cos(x)
and ∫ x sin(x)dx = −x cos(x) −
(− cos(x))dx
= −x cos(x) + sin(x) + C.
WARNING: This technique is not perfect!
There are exceptions to LIATE. Some of these can be solved using the order “ILATE” instead. Sometimes, something completely different needs to be con- sidered.
Example 2. ∫ x^3 ex
2 dx.
Following the LIATE rule, u = x^3 and dv = ex
2 dx. However, we would actually set u = x^2 and dv = xex
2 . u = x^2 dv = xex
2 dx du = 2xdx v = 12 ex 2 1
and so ∫ x^3 ex
2 dx = x^2
ex
2
ex
2 2 xdx
x^2 ex
2 −
xex
2 dx
x^2 ex
2 −
ex
2
=
ex
2 (x^2 − 1) + C.
Example 3. (^) ∫
sec^3 (x)dx.
Following the LIATE rule, u = 1 and dv = sec^3 (x)dx. However, we would actually set u = sec(x) and dv = sec^2 (x).
u = sec(x) dv = sec^2 (x)dx du = sec(x) tan(x)dx v = tan(x) and so ∫ sec^3 (x)dx = sec(x) tan(x) −
tan^2 (x) sec(x)dx
= sec(x) tan(x) −
(sec^2 (x) − 1) sec(x)dx
= sec(x) tan(x) −
sec^3 (x) − sec(x)
dx
= sec(x) tan(x) −
sec^3 (x)dx +
sec(x)dx
= sec(x) tan(x) −
sec^3 (x)dx + ln | sec(x) + tan(x)|.
Since the integral we are solving reappears, we need to add it to the left side to get
2
sec^3 (x)dx = sec(x) tan(x) + ln | sec(x) + tan(x)|.
Finally,
∫ sec^3 (x)dx =
sec(x) tan(x) +
ln | sec(x) + tan(x)| + C.