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Fractional Exponents: Converting Radicals to Exponents and Vice Versa, Lecture notes of Mathematics

Instructions on how to convert radical expressions to fractional exponents and vice versa. It includes examples of converting both radicals to exponents and exponents to radicals, as well as simplifying expressions using exponent rules. The document also emphasizes the importance of understanding the concepts from previous lessons, such as the Quotient Rule, Power Rule, and Product to a Power Rule.

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2021/2022

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16-week Lesson 3 (8-week Lesson 2) Fractional Exponents
1
In the previous set of notes, we found the following:
โˆš36=6
Re-writing the radicand 36 as 62, we have the following:
โˆš62=6
How can we re-write a radical (such as a square root) using an exponent?
In other words, 6 to the power of 2 to the power of what will result in 61,
or just 6. In this case, what exponent is the equivalent of a square root?
โˆš62=(62)๐‘ฅ=61
Using the Power Rule for Exponents, when a base is taken to a power, and
then to another power, the exponents are multiplied. So 2 times what
produces 1? 2๐‘ฅ=1
๐‘ฅ=1
2
So the answer is 1
2. A square root is equivalent to an exponent of 1
2.
โˆš62=(62)๐Ÿ
๐Ÿ =6
So a square root is equivalent to a power of 1
2, which is the reciprocal of
the index 2. The same is true for any radical; to express a radical as an
exponent, we simply need to take the reciprocal of the index of the radical.
Here are a few more examples of radicals and their exponent equivalents.
โˆš125
๐Ÿ‘=(125)1
3=5
โˆš๐‘ฅ
๐Ÿ’=(๐‘ฅ)1
4
โˆš๐‘ฆ2
๐Ÿ“=(๐‘ฆ2)1
5=๐‘ฆ2
5 (this example uses the Power Rule for Exponents)
pf3
pf4
pf5
pf8

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Download Fractional Exponents: Converting Radicals to Exponents and Vice Versa and more Lecture notes Mathematics in PDF only on Docsity!

In the previous set of notes, we found the following:

Re-writing the radicand 36 as 6

2

, we have the following:

2

How can we re-write a radical (such as a square root) using an exponent?

In other words, 6 to the power of 2 to the power of what will result in 6

1

or just 6. In this case, what exponent is the equivalent of a square root?

2

2

๐‘ฅ

1

Using the Power Rule for Exponents, when a base is taken to a power, and

then to another power, the exponents are multiplied. So 2 times what

produces 1?

So the answer is

1

2

. A square root is equivalent to an exponent of

1

2

2

2

๐Ÿ

๐Ÿ

= 6

So a square root is equivalent to a power of

1

2

, which is the reciprocal of

the index 2. The same is true for any radical; to express a radical as an

exponent, we simply need to take the reciprocal of the index of the radical.

Here are a few more examples of radicals and their exponent equivalents.

๐Ÿ‘

1

3

= 5

๐Ÿ’

1

4

2

๐Ÿ“

2

1

5

= ๐‘ฆ

2

5

(this example uses the Power Rule for Exponents)

Converting a radical ( โˆš

๐‘›

) to an exponent (๐‘ฅ

1

๐‘›

)

  • to write a radical as a fractional exponent, write the radicand as the

base and the reciprocal of the index as the exponent

o the radical expression โˆš๐‘ฅ

5

4

is equivalent to

5

1

4

, which

simplifies to ๐‘ฅ

5

4

by using the Power Rule for Exponents

o the radical expression ( โˆš

4

5

is equivalent to (๐‘ฅ

1

4

)

5

, which also

simplifies to ๐‘ฅ

5

4

by using the Power Rule for Exponents

  • be sure that the original radical exists, otherwise the new expression

is meaningless

Converting an exponent (๐‘ฅ

1

๐‘›

) to a radical (

โˆš

๐‘›

  • to write a fractional exponent as a radical, write the denominator of

the exponent as the index of the radical and the base as the radicand

o the expression ๐‘ฅ

3

5

can be written as a radical in two ways, both

of which are equivalent

3

5

= โˆš๐‘ฅ

3

5

3

5

= ( โˆš

5

3

o regardless of which way you choose to write the radical

expression, the index is the same (in this case 5 )

  • again, it is imperative that the radical exists, otherwise the expression

is meaningless

o โˆšโˆ’ 9 does not exist with real numbers, so it is meaningless to

write it as

1

2

o also, keep in mind the difference between

1

2

and โˆ’ 9

1

2

1

2

= โˆš

1

2

= โˆ’ 1 โˆ™ 9

1

2

โ– 

โ– 

e. โˆ’ 4

โˆ’

3

2

1

2

1

8

2

3

f. โˆ’ 32

โˆ’

2

5

64

125

โˆ’

1

3

โˆ’

3

2

1

2

1

2

3

8

2

3

1

4

3

2

1

2

( โˆš

1

3

)

2

( โˆš

8

3

)

2

1

( โˆš

4 )

3

1

2

( 1

)

2

( 2

)

2

1

( 2

)

3

1

2

1

4

1

8

1

8

1

8

1

8

๐ŸŽ

f.

Example 2: Simplify the following expression by converting to radical

form and/or by using Exponent Rules. Simplify completely and do NOT

leave negative exponents in your answers. If a solution does not exist in

real numbers, write DNE.

6

โˆ’

4

3

( 3 ๐‘ฅ

4

3

)

6

โˆ’

4

3

( 3 ๐‘ฅ

4

3

)

6

4

3

4

3

)

4

3

4

3 ( ๐‘ฅ

6

4

3

4

3

3

4

8

4

3

โˆ’ 8

4

โˆ’

20

3

๐Ÿ๐ŸŽ

๐Ÿ‘

Change a negative

exponent to a positive

exponent by taking

the reciprocal of the

expression.

To simplify a base (๐‘ฅ) to a

power

( 6

) to another power

(

4

3

), we multiply the powers,

giving us ๐‘ฅ

8

in this case.

๐‘ฅ

4

3

๐‘ฅ

8

can be simplified using the

Quotient Rule for exponents to

get ๐‘ฅ

4

3

โˆ’ 8

, which is ๐‘ฅ

โˆ’

20

3

Once again, to change a negative

exponent to a positive exponent

we take the reciprocal of the

expression. Since the factor

โˆ’

20

3

is already part of a

fraction, we can take itโ€™s

reciprocal by simply moving it

from the numerator to the

denominator.

The first thing to notice about

this expression is that ( 27 ๐‘ฅ

6

)

โˆ’

4

3

is a Product to a Power, while

( 3 ๐‘ฅ

4

3

) is just a product.

c. โˆ’ (

๐‘ฅ

3

64

โˆ’

4

3

4

โˆ’

3

2

๐‘ฅ

8

) d. (

๐‘ฅ

12

81

3

4

๐‘ฅ

9

27

โˆ’

2

3

1

4

โˆ’

4

5

)

64

๐‘ฅ

3

4

3

1

4

3

2

๐‘ฅ

8

(๐‘ฅ

12

)

3

4

81

3

4

27

๐‘ฅ

9

2

3

1

4

1

๐‘ฅ

4

5

64

4

3

( ๐‘ฅ

3

)

4

3

1

( โˆš

4 )

3

โˆ™๐‘ฅ

8

๐‘ฅ

9

( โˆš

81

4

)

3

(โˆ’ 27 )

2

3

(๐‘ฅ

9

)

2

3

1

4 ๐‘ฅ

4

5

( โˆš

64

3

)

4

๐‘ฅ

4

1

( 2

)

3

โˆ™๐‘ฅ

8

๐‘ฅ

9

27

( โˆšโˆ’ 27

3

)

2

๐‘ฅ

6

1

4 ๐‘ฅ

4

5

( 4

)

4

๐‘ฅ

4

1

8 ๐‘ฅ

8

๐‘ฅ

9

27

9

๐‘ฅ

6

1

4 ๐‘ฅ

4

5

256

๐‘ฅ

4

1

8 ๐‘ฅ

8

9 ๐‘ฅ

9

27 ๐‘ฅ

6

โˆ™ 4 ๐‘ฅ

4

5

256

๐‘ฅ

4

1

8 ๐‘ฅ

8

๐‘ฅ

3

3 โˆ™ 4 ๐‘ฅ

4

5

๐Ÿ๐Ÿ

๐‘ฅ

3 โˆ’

4

5

12

๐Ÿ๐Ÿ

๐Ÿ

๐Ÿ๐Ÿ

๐Ÿ๐Ÿ

๐Ÿ“

Once again, the expressions from Examples 2 and 3 can be difficult to

simplify completely, so be sure to spend time working on problems like

these not only in the homework, but also as you prepare for Exam #1. If

you need assistance understanding how to simplify these types of

expressions, please let me know.

Answers to Examples:

1 a. 81 ; 1b.

1

8

; 1c. ๐ท๐‘๐ธ ; 1 d.

9

4

; 1 e. 0 ; 1f. 1 ; 2 a.

1

27 ๐‘ฅ

20

3

3a. 27 ๐‘ฅ

22

15

; 3b. โˆ’

1

128 ๐‘ฅ

13

2

; 3c. โˆ’

32

๐‘ฅ

12

; 3d.

1

12

11

5

;