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Exam 2 Sample Answers | Applied Calculus | MA 139, Exams of Calculus

Material Type: Exam; Class: Applied Calculus; Subject: Mathematics; University: Southeast Missouri State University; Term: Spring 2009;

Typology: Exams

Pre 2010

Uploaded on 08/08/2009

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MA-139 Applied Calculus - Exam 2 SAMPLE ANSWERS
March 25, 2009
1. y=๎˜€1 + 13
6(x๎˜€1).
2. Find the โ€ฆrst derivative of the following functions:
(a) f0(x) = 4
3x1=3(b) f(x) = ๎˜€1
x2
(c) f(x) = ๎˜€x2+ 4x+ 4๎˜(2x๎˜€1)๎˜€1=2๎˜€(2x+ 4)p2x๎˜€1
2x๎˜€1(d) f0(t) = ๎˜€1
(t๎˜€1)2
(e) f0(x) = 1
8x๎˜€1=2๎˜€2x๎˜€3=2(f) p0(s) = ๎˜€1
2s๎˜€3=2
(g) dy
dx = 31
2=7
2(h) dy
dx = (x๎˜€1) ๎˜€2x+x๎˜€1=2๎˜+๎˜€x2+ 2px+ 7๎˜
(i) y=๎˜€x๎˜€x2+ 1๎˜๎˜€1=2(j) f0(x) = 2 ๎˜€x๎˜€1๎˜€x๎˜๎˜€๎˜€x๎˜€2๎˜€1๎˜
3. Complete the table below, given that h(x) = f(g(x)) and p(x) = f(x)g(x):
x f (x)f0(x)g(x)g0(x)h(x)h0(x)p(x)p0(x)
1 2 3 2 ๎˜€2
3๎˜€4๎˜€2 4 14
3
2๎˜€4 2 1 5 2 15 ๎˜€4๎˜€18
4. (a) Find dy
dx =2x+ 2xy
3๎˜€x2.
(b) Find dy
dx =
1
2x๎˜€1=2y๎˜€1=2
1
2x1=2y๎˜€3=2๎˜€1
=1
xy๎˜€1๎˜€2x1=2y1=2=y
x๎˜€2x1=2y3=2.
5. ds
dt =48
12 ๎˜€hwhere his your height.
6. Critical points: x=๎˜€p2(neither), x= 0 (relative maximum), and x=p2(neither).
7. f00 (x) = 12x2๎˜€36x; concave up: x < 0and x > 3; concave down: 0< x < 3.
8. x= 10;500.
9. (This one will only ask you to label critical points, and increasing and decreasing areas.)
10. The order is g(x),f(x),f0(x), and f00 (x).
1

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MA-139 Applied Calculus - Exam 2 SAMPLE ANSWERS

March 25, 2009

  1. y = 1 +

(x 1).

  1. Find the ร–rst derivative of the following functions: (a) f 0 (x) =

3 x

1 = (^3) (b) f (x) = 1 x^2 (c) f (x) =

x^2 + 4x + 4

(2x 1)^1 =^2 (2x + 4)

p 2 x 1 2 x 1 (d) f 0 (t) =

(t 1)^2 (e) f 0 (x) =

x^1 =^2 2 x^3 =^2 (f) p^0 (s) =

s^3 =^2 (g) dy dx = 3

2 (h)^

dy dx = (x^ ^ 1)^

2 x + x^1 =^2

x^2 + 2

p x + 7

(i) y = x

x^2 + 1

(j) f 0 (x) = 2

x^1 x

x^2 1

  1. Complete the table below, given that h (x) = f (g (x)) and p (x) = f (x) g (x): x f (x) f 0 (x) g (x) g^0 (x) h (x) h^0 (x) p (x) p^0 (x) 1 2 3 2 2 3
  1. (a) Find dy dx

2 x + 2xy 3 x^2

(b) Find dy dx =

x^1 =^2 y^1 =^2 1 2 x^1 =^2 y^3 =^2 1

xy^1 2 x^1 =^2 y^1 =^2

y x 2 x^1 =^2 y^3 =^2

ds dt

12 h where h is your height.

  1. Critical points: x =

p 2 (neither), x = 0 (relative maximum), and x =

p 2 (neither).

  1. f 00 (x) = 12x^2 36 x; concave up: x < 0 and x > 3 ; concave down: 0 < x < 3.
  2. x = 10; 500.
  3. (This one will only ask you to label critical points, and increasing and decreasing areas.)
  4. The order is g (x), f (x), f 0 (x), and f 00 (x).