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Solving for IDQ in an Electrical Circuit: ECE250 HW4 Problem 2 - Prof. Marc E. Herniter, Assignments of Electrical and Electronics Engineering

Rose-Hulman Institute of Technology (RHIT)Electrical and Electronics Engineering

Prof. Marc E. Herniter

The steps to solve for idq (current through the diode) in an electrical circuit given certain voltage and resistance values. The problem is part of homework 4 in the ece250 (electrical circuits i) course at indiana state university. Students are required to apply ohm's law and the diode equation to find the idq values for three different input currents.

Typology: Assignments

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Uploaded on 08/18/2009

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Download Solving for IDQ in an Electrical Circuit: ECE250 HW4 Problem 2 - Prof. Marc E. Herniter and more Assignments Electrical and Electronics Engineering in PDF only on Docsity!

V

V =0.877 V

V

DQ

I

DQ

R

D

R

D

R =0.026 Ω

D

V

T

N I

DQ

V

DQ

V =0.89 V

DQ

N V

T

⋅ ln

I

DQ

I

S

I

DQ

Solve for I (^) :=500mA DQ

= 500 mA

V

V =0.794 V

V

DQ

I

DQ

R

D

R

D

R =0.13 Ω

D

V

T

N I

DQ

V

DQ

V =0.807 V

DQ

N V

T

⋅ ln

I

DQ

I

S

I

DQ

Solve for I (^) :=100mA DQ

= 100 mA

V

V =0.559 V

V

DQ

I

DQ

R

D

R

D

R =13.004 Ω

D

V

T

N I

DQ

V

DQ

V =0.572 V

DQ

N V

T

⋅ ln

I

DQ

I

S

I

DQ

Solve for I (^) :=1mA DQ

= 1 mA

I N :=1.

S

− 9 V := ⋅ ⋅amp T

:=25.8 mV⋅

Solving for IDQ in an Electrical Circuit: ECE250 HW4 Problem 2 - Prof. Marc E. Herniter, Assignments of Electrical and Electronics Engineering

Related documents

Partial preview of the text

Download Solving for IDQ in an Electrical Circuit: ECE250 HW4 Problem 2 - Prof. Marc E. Herniter and more Assignments Electrical and Electronics Engineering in PDF only on Docsity!

V

V =0.877 V

V

DQ

I

DQ

R

D

R

D

R =0.026 Ω

D

V

T

N I

DQ

V

DQ

V =0.89 V

DQ

N V

T

I

DQ

I

S

I

DQ

V

V =0.794 V

V

DQ

I

DQ

R

D

R

D

R =0.13 Ω

D

V

T

N I

DQ

V

DQ

V =0.807 V

DQ

N V

T

I

DQ

I

S

I

DQ

V

V =0.559 V

V

DQ

I

DQ

R

D

R

D

R =13.004 Ω

D

V

T

N I

DQ

V

DQ

V =0.572 V

DQ