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Sodium bicarbonate decompostion into sodicum carbonate, water and carbon diaxoide. Complete lab manul with worksheet.
Typology: Lab Reports
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Goal: To experimentally determine decomposition reaction of sodium hydrogen carbonate on reaction stoichiometry. Introduction Stoichiometry is the study of mass relationships in chemistry. In this lab, you will decompose baking soda (sodium hydrogen carbonate or sodium bicarbonate) and use the mass relationships to determine how baking soda decomposes. Baking soda is commonly used in baking to provide a โriseโ to baked goods. When baking soda decomposes it produces a gas (carbon dioxide) which is trapped in pockets and giving the baked goods an airy texture. Sodium bicarbonate may be more familiar to you as baking soda. There are three theoretically possible chemical reactions that could occur during the thermal decomposition of baking soda.
By comparing the theoretical yields of the possible solid products with the actual experimental yield of the product, you will be able to determine which of the above decomposition reactions occurred. In this experiment, you will determine the products from the thermal decomposition of sodium bicarbonate. The experiment is straightforward. A sample of sodium bicarbonate is weighed and heated. The final product will be weighed and the mass of product will be compared to the theoretical yield of the three possible products to determine how sodium bicarbonate decomposes, and whether its decomposition gives different products when heated to a low temperature versus a high temperature. Laboratory Activity Equipment hot plate analytical top-loader balance clean dry beaker Beaker tongs Chemicals NaHCO 3 (s) Safety Hazards โ Caution โ hot plates are hot! Even when they may not look hot. When determining if a beaker is still hot, slowly bring the back of your fingers towards it. If you sense any heat radiating from the beaker, do not touch, wait! PROCEDURE
weights.
Record all masses to the maximum number of sig figs Run 1 200ยฐC Run 2 400ยฐC
___NaHCO 3 (s) โ ___NaOH(s) + ___CO 2 (g)
___NaHCO 3 (s) โ ___Na 2 O(s) + ___CO 2 (g) + ___H 2 O(g)
___NaHCO 3 (s) โ ___Na 2 CO 3 (s) + ___CO 2 (g) + ___H 2 O(g)
from each of the possible decomposition reactions, then calculate the percent yield by dividing your actual yield by the theoretical yield you calculate for each reaction. Percent yield = | ๐๐๐ก๐ข๐๐ ๐ฆ๐๐๐๐ ๐กโ๐๐๐๐๐ก๐๐๐๐ ๐ฆ๐๐๐๐|^ x 100 Reaction A ___NaHCO 3 (s) โ ___ NaOH(s) + ___CO 2 (g) Run 1: Initial grams of NaHCO 3 = __________________ Theoretical yield (grams) of NaOH:___________ Percent yield (Run 1) = ____________________ Run 2: Initial grams of NaHCO 3 = __________________ Theoretical yield (grams) of NaOH:___________ Percent yield (Run 2) = ____________________ Reaction B ___NaHCO 3 (s) โ ___ Na 2 O(s) + ___CO 2 (g) + ___H 2 O(g) Run 1: Initial grams of NaHCO 3 = __________________ Theoretical yield (grams) of Na 2 O:___________ Percent yield (Run 1) = ____________________
What about during Run 2 (heated to 400ยฐC)? Did they form the same product, or different products? Was this expected or unexpected? Explain briefly.