Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Calculating Atomic Masses from Isotopic Composition, Lecture notes of Chemistry

The concept of atomic mass and how it is calculated using the masses and fractional abundances of naturally occurring isotopes. It provides examples and practice problems for calculating the atomic masses of various elements, including silicon, gallium, bromine, and titanium.

Typology: Lecture notes

2021/2022

Uploaded on 09/12/2022

jeny
jeny 🇺🇸

4.6

(14)

251 documents

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Atomic Mass
One atomic mass unit (amu): the mass exactly equal to one-twelfth the mass of one
carbon-12 atom that has six protons and six neutrons.
1 atom of carbon-12 = 12 amu
1 amu =
mass of one C-12 atom
12
1 amu = 1.66054 x 10
-24
g and 1 g = 6.02214 x 10
23
amu
Average Atomic Mass: the weighted average of the masses of the naturally occurring
isotopes of the element; the mass of the atom in atomic mass units
Average Atomic Mass = (fractional abundance of isotope n) × (mass of isotope
n)
Isotopes: atoms with identical atomic numbers but different mass numbers (that is,
same number of protons but different numbers of neutrons)
Average atomic mass of carbon = (0.09890)(12.00000 amu) + (0.0110)(13.00335 amu)
= 12.0107 amu
Example
If chlorine is 75.78 % Cl-35 with a mass of 34.9689 amu and the rest Cl-37 with a mass
of 36.9659 amu, find chlorine’s atomic mass.
Cl atomic mass = 0.7578 x 34.9689 + (1 - 0.7578) × 36.9659 = 35.45 amu
Atomic Number
Atomic Symbol
Atomic Weight
Carbon Isotopes
Atomic Number
(number of protons)
Mass number (number of
protons plus neutrons)
pf2

Partial preview of the text

Download Calculating Atomic Masses from Isotopic Composition and more Lecture notes Chemistry in PDF only on Docsity!

Atomic Mass

One atomic mass unit (amu) : the mass exactly equal to one-twelfth the mass of one carbon-12 atom that has six protons and six neutrons. 1 atom of carbon-12 = 12 amu

1 amu =

mass of one C-12 atom

1 amu = 1.66054 x 10 -24^ g and 1 g = 6.02214 x 10^23 amu

Average Atomic Mass : the weighted average of the masses of the naturally occurring isotopes of the element; the mass of the atom in atomic mass units

Average Atomic Mass = ∑ (fractional abundance of isotope n) × (mass of isotope n)

Isotopes : atoms with identical atomic numbers but different mass numbers (that is, same number of protons but different numbers of neutrons)

Average atomic mass of carbon = (0.09890)(12.00000 amu) + (0.0110)(13.00335 amu) = 12.0107 amu

Example

If chlorine is 75.78 % Cl-35 with a mass of 34.9689 amu and the rest Cl-37 with a mass of 36.9659 amu , find chlorine’s atomic mass.

Cl atomic mass = 0.7578 x 34.9689 + (1 - 0.7578) × 36.9659 = 35.45 amu

Atomic Number

Atomic Symbol Atomic Weight

Carbon Isotopes

Atomic Number (number of protons)

Mass number (number of protons plus neutrons)

Atomic mass = (Fraction of isotope 1 x Mass of isotope 1) +

(Fraction of isotope 2 x Mass of isotope 2) +

(Fraction of isotope 3 x Mass of isotope 3) + ……

Practice Problems

  1. Three isotopes of silicon occur in nature. 28 Si (92.23%), which has an atomic mass of 27.97693 amu; 29 Si (4.68%), which has an atomic mass of 28.97649 amu; and (^30) Si (3.09%), which has an atomic mass of 29.97377 amu. Calculate the atomic weight of silicon.
  2. Gallium has two naturally occurring isotopes: Ga-69 with mass 68.9256 amu and a natural abundance of 60.11%, and Ga-71 with mass 70.9247 amu and a natural abundance of 39.89%. Calculate the atomic mass of gallium.
  3. Bromine has two naturally occurring isotopes (Br-79 and Br-81) and an atomic mass of 79.904 amu. (a) If the natural abundance of Br-79 is 50.69%, what is the natural abundance of Br- 81? (b) If the mass of Br-81 is 80.9163 amu, what is the mass of Br-79?
  4. Titanium has five common isotopes: 46 Ti (8.25%), 47 Ti (7.44%). 48 Ti (73.72%), 49 Ti (5.41%), 50 Ti (5.18%). What is the average atomic mass of titanium?

Isotope Aundance (fraction) Atomic mass (amu) (^46) Ti 0.0825 45. (^47) Ti 0.0744 46. (^48) Ti 0.7372 47. (^49) Ti 0.0541 48. (^50) Ti 0.0518 49.

References: Tro, Chemistry: A Molecular Approach 2 nd^ ed., Pearson Brown/LeMay/Bursten, Chemistry: The Central Science, 12th^ ed., Pearson

Answers

47.7 amu 4. (a) 49.31% (b) 78.91 amu 3. 69.72 amu 2. 28.09 amu 1.