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Analysis of Mendelian Ratios - Genetics - Lecture Slides | BIOL 358, Exams of Genetics

Material Type: Exam; Class: GENETICS; Subject: Biological Sciences; University: Idaho State University; Term: Spring 2006;

Typology: Exams

Pre 2010

Uploaded on 09/02/2009

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ANALYSIS OF MENDELIAN
RATIOS:
PROBABILITY AND THE
CHI-SQUARE TEST
Genetic – BIOL 358
Lecture 5
24 January 2006
PROBABILITY AND GENETIC EVENTS
Probability Theory
1. Probability of occurrence (P)
P = # of defined outcomes / total # of possible outcomes
Example: P of getting 3 in a die toss
1 chance (of a 3) / 6 possible outcomes = 1/6
Probability of Multiple Events
1. Product Rule
-probability of 2 independent events
occurring together is equal to the product of
their individual probabilities
Example: A couple, both of whom are normal,
have a child that is an albino. The couple was
planning to have 2 more children; what is the
probability that both will be albino?
pf3
pf4
pf5

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ANALYSIS OF MENDELIAN

RATIOS:

PROBABILITY AND THE

CHI-SQUARE TEST

Genetic – BIOL 358

Lecture 5

24 January 2006

PROBABILITY AND GENETIC EVENTS

Probability Theory

1. Probability of occurrence (P)

P = # of defined outcomes / total # of possible outcomes

Example: P of getting 3 in a die toss

1 chance (of a 3) / 6 possible outcomes = 1/

Probability of Multiple Events

1. Product Rule

-probability of 2 independent events occurring together is equal to the product of their individual probabilities

  • Example: A couple, both of whom are normal, have a child that is an albino. The couple was planning to have 2 more children; what is the probability that both will be albino?

Probability of Multiple Events

2. Sum Rule

-probability of either of 2 independent events occurring is equal to the sum of their individual probabilities -either or, but not both occur

Example: For the previous couple, what is the

probability that either both children will be albino or both will be normal?

EVALUATING GENETIC DATA

The Chi-Square Test

1. Compares an observed outcome to an

expected outcome (based on a genetic

hypothesis)

2. Asks if the difference between observed

and expected is due solely to chance

deviations

3. Dependent upon sample size

-chance deviations are more likely when sample size is small

Chance and Mendelian Ratios

4. Chance events can affect Mendelian

ratios

-segregation of alleles is affected by chance -independent assortment is affected by chance -fertilization is affected by chance

5. Chance deviations in any one of the above

can alter observed Mendelian ratios

Monohybrid Example

Use a Chi-Square Test:

-first calculate expected frequencies of each phenotype 3/4 should be tall 1/4 should be dwarf

-then calculate X 2 value

Monohybrid Example

Is your calculated X^2 significant?

Compare your calculated X 2 to the tabled X^2

-need to know degrees of freedom df = N - 1 Where N = the number of phenotypic classes Our example, df = 2 - 1 = 1

Critical Value of Chi-square

Need to set a critical value to interpret your X^2

5% is used by scientific convention -this means that if your calculated X^2 is larger than the tabled X^2 at 5% then the difference is REAL, not due to chance -if your calculated X 2 is less than the tabled X^2 at 5%, then the difference is due solely to CHANCE

X^2 , P < 0.05, 1 df = 3.841 (page 63 in text)

In our example, X 2 = 0.60, definitely less than 3.841, thus deviation is due to chance, these observed numbers fit a Mendelian 3:1 ratio

Dihybrid Example

Consider the following observed F2 offspring:

Round, Yellow Round, Green Wrinkled, Yellow Wrinkled, Green 315 108 101 32

Do these observed results fit a 9:3:3:1 ratio predicted if these traits are inherited in a Mendelian fashion?