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Class: TOPICS IN PROBABILITY THEORY AND STOCHASTIC PROCESSES; Subject: Mathematics; University: Kent State University;
Typology: Study notes
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Properties of the stochastic integral:
aX(s) + bY (s)dW (s) = a
∫ (^) t
0
X(s)dW (s) + b
∫ (^) t
0
Y (s)dW (s)
∫ (^) t 0 X(s)dW^ (s)] = 0
∫ (^) t 0 X(s)dW^ (s)
(^2) ] = ∫^ t 0 E[Y^ (s)
(^2) ]ds
∫ (^) t 0 g(s)dW^ (s). Then^ Y^ is adapted to^ FW^.
If It =
∫ (^) t 0 g(s)dW^ (s), then^ I^ is a^ F
W (^) -martingale.
Examples: Models that describe the dynamic behavior of asset prices contain invention terms that represent unpredictable news. As a result, an integral of the form ∫ (^) t+∆t
t
σ(s)dW (s)
is a sum of unpredictable disturbances that affect asset prices during an interval of length ∆t. Now, if each increment is unpredictable given the information set at time t, the sum of these increments should also be unpredictable. This means that
∫ (^) t+∆t
t
σ(s)dW (s)|Ft) = 0
But this is equivalent to:
∫ (^) t+∆t
0
σ(s)dW (s)|Ft) = E(
∫ (^) t
0
σ(s)dW (s)|Ft) =
∫ (^) t
0
σ(s)dW (s)
which is exactly the martingale property of the stochastic integral. Hence, the existence of unpre- dictable innovation terms in equations describing the dynamics of asset prices coincides well with the martingale property of the Ito integral. Let’s look at particular case: σ(s) = σ, a constant. Then: (^) ∫ (^) t+∆t
t
σ(s)dW (s) = σ(Wt+∆t − Wt)
Exercises:
∫ (^) t
0
E(X(s)Y (s))ds
where I(X) is the si of X with respect to W. 2) Verify the equality: ∫ (^) t
0
W (s)dW (s) =
2 W^ (t)
2 t
using the definition of the stochastic integral.
Quadratic variation of a martingale:
Theorem:
Let M be a martingale such that for any t ≥ 0, E[(Mt)^2 ] < ∞ (i.e. square integrable martingale).Then the quantity n∑− 1
k=
(k + 1)t n )^ −^ M^ (^
kt n )]
2
converges in L^2 to a r.v. A(t) that is called quadratic variation of M, and it is denoted by A(t) =< M > (t).
Properties:
A is a stochastic process that is adapted to FM^ , i.e. A(t) ∈ FtM.
A(t) is non-decreasing a.s.
Remark:
For B.m. we have
E[
n∑− 1
k=
(k + 1)t n )^ −^ B(^
kt n )]
n∑− 1
k=
E[[B( (k^ + 1)t n
) − B( kt n
n∑− 1
k=
t n
= t
Exercise: Show that < B > (t) = t, < W > (t) = t, if B is a B.m.
Remark:
The converse is also true (Paul Levy): If M is a square integral martingale that is a.s. continuous, and if < M > (t) = t, then M is a B.m.
Interpretation:
What is the interpretation of quadratic variation?
n∑− 1
k=
|f ( t(k^ n+ 1) ) − f ( tkn )|1+α^ →? as n → ∞
For B.m. (∗) → ∞ if α < 1 ; (∗) → t if α = 1 : (∗) → 0 if α > 1