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3 Practice Problems on Linear Algebra and Applications - Quiz 3 | MATH 240, Quizzes of Linear Algebra

Material Type: Quiz; Class: Linear Algebra and Applications; Subject: MATHEMATICAL SCIENCES; University: Northern Illinois University; Term: Fall 2007;

Typology: Quizzes

Pre 2010

Uploaded on 08/17/2009

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MATH 240 QUIZ 3 NAME SOLUTIONS
Prof. J. Beachy Friday, 9/14/2007 Score / 20
1. (6 pts) Find the reduced row echelon form of the matrix A=cos θsin θ
sin θcos θ.
Remember that a b
c d is invertible precisely when the determinant ad bc is nonzero. The determinant of the
given matrix is cos2θ+ sin2θ= 1, so the matrix is invertible, and then our theorems guarantee that it can be row
reduced to the identity matrix.
2. (7 pts) The matrix A=1 2
3 4 is invertible. Find a sequence of elementary matrices that will reduce Ato the
identity.
1 0
3 1 1 2
3 4 =1 2
02
1 0
0
1
2 1 0
3 1 1 2
3 4 =1 0
0
1
2 1 2
02=1 2
0 1
12
0 1 1 0
0
1
2 1 0
3 1 1 2
3 4 =12
0 1 1 2
0 1 =1 0
0 1
E1=1 0
3 1 E2=1 0
0
1
2E3=12
0 1
This isn’t part of the question, but we can use this sequence to write Aas a product of elementary matrices.
1 2
3 4 =1 0
3 1 11 0
0
1
2112
0 1 1
=1 0
3 1 1 0
02 1 2
0 1
3. (7 pts) Find the inverse of the following matrix (if it exists): A=
111
123
011
111100
123010
011001
111 100
012110
011 001
111 100
011 001
012110
100 101
0 1 1 0 0 1
0011 1 1
1 0 0 1 0 1
010 11 2
0011 1 1
111
123
011
1
=
1 0 1
11 2
1 1 1

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MATH 240 QUIZ 3 NAME SOLUTIONS

Prof. J. Beachy Friday, 9/14/2007 Score / 20

  1. (6 pts) Find the reduced row echelon form of the matrix A =

[

cos θ sin θ − sin θ cos θ

]

Remember that

[

a b c d

]

is invertible precisely when the determinant ad − bc is nonzero. The determinant of the

given matrix is cos^2 θ + sin^2 θ = 1, so the matrix is invertible, and then our theorems guarantee that it can be row reduced to the identity matrix.

  1. (7 pts) The matrix A =

[

]

is invertible. Find a sequence of elementary matrices that will reduce A to the

identity. [ 1 0 − 3 1

] [

]

[

]

[

] [

] [

]

[

] [

]

[

]

[

] [

] [

] [

]

[

] [

]

[

]

E 1 =

[

]

E 2 =

[

]

E 3 =

[

]

This isn’t part of the question, but we can use this sequence to write [ A as a product of elementary matrices. 1 2 3 4

]

[

]− 1 [

]− 1 [

]− 1

[

] [

] [

]

  1. (7 pts) Find the inverse of the following matrix (if it exists): A =

− 1